Nernst Equation Calculator
ChemistryCalculate actual cell potential E using the Nernst equation: E = E° − (RT/nF)ln(Q). Enter standard potential, electron count, reaction quotient, and temperature.
Cell Potential (E)
What is a Nernst?
The Nernst Equation Calculator computes the actual electrochemical cell potential E at any temperature and concentration conditions using E = E° − (RT/nF)ln(Q). Enter the standard cell potential E°, number of electrons n, reaction quotient Q, and temperature to get the actual cell voltage, the RT/nF factor, and the Gibbs energy at those conditions.
The Nernst equation bridges the standard cell potential (measured at 1 M, 1 atm, 25°C) with real-world conditions where concentrations differ from 1 M. A battery discharges as reactants are consumed and products accumulate — Q increases, E decreases. The Nernst equation describes this voltage drop quantitatively throughout the discharge cycle.
The connection between the Nernst equation and thermodynamics is direct: ΔG = −nFE = −nFE° + RT·ln(Q) = ΔG° + RT·ln(Q), which is the fundamental Gibbs energy-reaction quotient relationship. The Nernst equation is simply the electrochemical expression of this universal thermodynamic relationship. The Cell EMF Calculator computes the standard potential E°; this calculator applies the Nernst correction to find E at actual conditions.
How to use this Nernst calculator
- Enter Standard Cell Potential E° in volts. Compute it from reduction potentials using the Cell EMF Calculator, or look it up in a reference table.
- Enter n — the number of electrons transferred in the balanced redox equation.
- Calculate and enter Q — products over reactants at current conditions. Pure solids and liquids are omitted. Gases use partial pressures in atm.
- Enter the Temperature in °C.
- Read Cell Potential E — the actual voltage under these conditions.
- Check ΔG to see whether the reaction is thermodynamically favourable at these conditions.
Formula & Methodology
Nernst equation:E = E° − (RT/nF) × ln(Q) RT/nF at 25°C = 0.025693/n V per unit ln(Q) At 25°C: E = E° − (0.05916/n) × log₁₀(Q) [approximate, widely used]Gibbs energy at actual conditions:ΔG = −nFE = −n × 96485 × E / 1000 [kJ/mol]Worked example — lead-acid battery during discharge: Lead-acid cell: PbO₂ + Pb + 4H⁺ + 2SO₄²⁻ → 2PbSO₄ + 2H₂O, E° = 2.05 V, n = 2. At 25°C with [H⁺] = 3.75 M (specific gravity 1.28 electrolyte) and [SO₄²⁻] = 1.0 M:Q = 1 / ([H⁺]⁴ × [SO₄²⁻]²) = 1 / (3.75⁴ × 1²) = 1 / 197.8 = 0.00506 log₁₀(Q) = log₁₀(0.00506) = −2.296 E = 2.05 − (0.05916/2) × (−2.296) = 2.05 + 0.02958 × 2.296 = 2.05 + 0.0679 = 2.118 VA fully charged lead-acid cell with concentrated sulfuric acid runs at approximately 2.12 V rather than the standard 2.05 V, because the high acid concentration makes Q < 1 (pushing E above E°). As the cell discharges, [H⁺] and [SO₄²⁻] decrease, Q rises, and E falls — consistent with the observed 1.75–2.10 V operational range.
Frequently Asked Questions