Cell EMF Calculator
ChemistryCalculate standard cell potential E°cell = E°cathode − E°anode, Gibbs free energy ΔG°, and equilibrium constant K for any electrochemical cell.
E°cell
What is a Cell EMF?
The Cell EMF Calculator computes the standard cell potential E°cell = E°cathode − E°anode for any galvanic or electrolytic cell, along with the Gibbs free energy ΔG° and equilibrium constant K. Enter the standard reduction potentials (from an electrochemical series table) for the two half-reactions and the number of electrons transferred.
Standard electrode potentials are the fundamental language of electrochemistry. Every galvanic cell — from a simple zinc-copper Daniell cell to a lithium-ion battery — can be characterised by E°cell, which encapsulates the entire thermodynamic driving force of the cell reaction. A positive E°cell means the cell does work spontaneously (like a battery); a negative E°cell means external work must be done to drive the reaction (electrolysis). The Nernst Equation Calculator extends this to non-standard conditions.
The three outputs — E°cell, ΔG°, and log₁₀(K) — are all equivalent representations of the same thermodynamic information. ΔG° = −nFE°cell tells you the maximum work the cell can do; log₁₀(K) = nE°cell/0.05916 tells you where the equilibrium lies. A cell voltage of just 0.1 V per electron transferred corresponds to K ≈ 10^1.7 ≈ 50 — products already heavily favoured. This calculator makes these conversions automatic.
How to use this Cell EMF calculator
- Look up the Cathode Reduction Potential (E°) from an electrochemical series table for the half-reaction that undergoes reduction. The species with the higher E° always acts as cathode.
- Look up the Anode Reduction Potential (E°) for the half-reaction that undergoes oxidation. Use the reduction potential value (not the oxidation potential) — the formula subtracts it automatically.
- Enter n, the number of moles of electrons transferred in the balanced overall equation. (Count electrons in the balanced half-reactions.)
- Read E°cell — if positive, the reaction is spontaneous.
- Use ΔG° and log₁₀(K) to quantify the thermodynamic driving force and equilibrium position.
Formula & Methodology
Standard cell potential:E°cell = E°cathode − E°anode (both as reduction potentials)Gibbs free energy:ΔG° = −nFE°cell F = 96,485 C/mol (Faraday constant)Equilibrium constant:log₁₀(K) = nFE° / (R × T × ln10) = nE°cell / 0.05916 (at 25°C)Worked example — Daniell cell (Cu²⁺/Cu || Zn²⁺/Zn): Cathode: Cu²⁺ + 2e⁻ → Cu, E° = +0.34 V Anode: Zn²⁺ + 2e⁻ → Zn, E° = −0.76 V (Zn is oxidised, but we use E°reduction = −0.76 V) n = 2E°cell = 0.34 − (−0.76) = 1.10 V ΔG° = −2 × 96485 × 1.10 / 1000 = −212.3 kJ/mol log₁₀(K) = 2 × 96485 × 1.10 / (8.314 × 298.15 × 2.3026) = 37.21 K = 10^37.21 ≈ 1.6 × 10³⁷The Daniell cell delivers 1.10 V, releases 212 kJ per mole of reaction, and has an equilibrium constant so large that the reaction is effectively irreversible. This explains why zinc spontaneously corrodes in contact with copper sulfate solution.
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