Gibbs Free Energy Calculator
ChemistryCalculate the Gibbs free energy change ΔG from enthalpy ΔH, entropy ΔS, and temperature T using ΔG = ΔH − TΔS. Determine if a reaction is spontaneous at a given temperature.
Gibbs Free Energy (ΔG°)
What is a Gibbs Free Energy?
The Gibbs Free Energy Calculator computes the standard Gibbs free energy change (ΔG°) from the enthalpy change (ΔH°), entropy change (ΔS°), and temperature (T) using the fundamental thermodynamic equation ΔG° = ΔH° − TΔS°. It also derives the equilibrium constant Kc from ΔG° = −RT ln(Kc) and classifies the reaction as spontaneous, non-spontaneous, or at equilibrium.
Gibbs free energy is the master thermodynamic criterion for chemical spontaneity. While enthalpy and entropy each capture part of the thermodynamic picture — energy release vs. disorder — ΔG combines both into a single number that directly answers whether a reaction will proceed. A negative ΔG at a given temperature means the reaction is spontaneous at those conditions; a positive ΔG means it is not. At ΔG = 0, the system is at equilibrium.
The temperature in the formula ΔG = ΔH − TΔS acts as a "weight" on the entropy term. This is why some reactions are spontaneous only above certain temperatures (entropy-driven at high T) and others only below certain temperatures (enthalpy-driven at low T). This temperature crossover behaviour is calculated directly by setting ΔG = 0 and solving for T = ΔH/ΔS.
Together with the Entropy Calculator (which extracts ΔS° from ΔH° and ΔG°) and the Equilibrium Constant Calculator (which connects Kc to ΔG°), this tool completes the core chemical thermodynamics toolkit.
How to use this Gibbs Free Energy calculator
- Find the standard enthalpy change ΔH° from a thermochemical table (NIST, NCERT appendix, or CRC Handbook). Enter it in kJ/mol in the Enthalpy Change (ΔH°) field — negative for exothermic.
- Find the standard entropy change ΔS° from the same source (or calculate it as the difference of standard molar entropies). Enter it in J/mol·K in the Entropy Change (ΔS°) field — note the units are J/mol·K, not kJ/mol·K.
- Enter the temperature in Kelvin in the Temperature field. For standard conditions, use 298 K; for a different temperature, note that ΔH° and ΔS° are assumed temperature-independent in this calculation.
- Read ΔG° (kJ/mol) and the Spontaneity verdict.
- Use the Kc output to connect to equilibrium analysis — compare to Kc values measured at the same temperature.
Formula & Methodology
Gibbs–Helmholtz equation:ΔG° = ΔH° − T × ΔS° (ΔH° in kJ/mol, T in K, ΔS° converted from J/mol·K to kJ/mol·K by ÷ 1000)Equilibrium constant from ΔG°:ΔG° = −RT ln(Kc) Kc = exp(−ΔG° × 1000 / (R × T)) [R = 8.314 J/(mol·K)]Crossover temperature (ΔG = 0):T_cross = ΔH° / ΔS° (ΔH° in J/mol, ΔS° in J/mol·K)Worked example — Haber process for ammonia: N₂(g) + 3 H₂(g) → 2 NH₃(g): ΔH° = −92.4 kJ/mol, ΔS° = −198.3 J/mol·K At T = 298 K:ΔG° = −92.4 − (298 × −0.1983) = −92.4 + 59.1 = −33.3 kJ/mol (spontaneous at 298 K) Kc = exp(33,300 / (8.314 × 298)) = exp(13.44) = 6.8 × 10⁵At T = 773 K (industrial operating temperature):ΔG° = −92.4 − (773 × −0.1983) = −92.4 + 153.3 = +60.9 kJ/mol (non-spontaneous at 773 K under standard conditions) Crossover: T = 92,400 / 198.3 = 466 KAbove 466 K, the Haber process is thermodynamically non-spontaneous under standard conditions — explaining why it is run at high pressure (to shift equilibrium) and uses a catalyst (to achieve acceptable rate at the lower temperatures that are thermodynamically favourable).
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