Thermal Conductivity Converter
ScienceConvert thermal conductivity between W/m·K, BTU/(hr·ft·°F), cal/(s·cm·°C), and BTU·in/(hr·ft²·°F) — used for materials science and insulation design.
| Watts per Metre-Kelvin (W/m·K) | 1 |
| BTU per Hour-Foot-°F (BTU/(hr·ft·°F)) | 0.57779087 |
| Calories per Second-Centimetre-°C (cal/(s·cm·°C)) | 0.0023900574 |
| BTU·in per Hour-Foot²-°F (BTU·in/(hr·ft²·°F)) | 6.9334665 |
What is a Thermal Conductivity?
The Thermal Conductivity Converter converts thermal conductivity between watts per metre-Kelvin (the SI unit), BTU per hour-foot-°F (the standard imperial unit), calories per second-centimetre-°C (a CGS unit still used in some scientific literature), and BTU·inch per hour-foot²-°F (the common US insulation "k-value" unit). Thermal conductivity is an intrinsic material property describing how readily heat passes through a substance.
Enter a value in any supported unit and the converter calculates the equivalent instantly. For the related quantity that accounts for specific component geometry, see the Thermal Resistance Converter.
How to use this Thermal Conductivity calculator
- Choose your starting unit from the source dropdown — for example, "Watts per Metre-Kelvin (W/m·K)".
- Enter the numeric value you want to convert in the input field.
- Choose your target unit from the destination dropdown — for example, "BTU per Hour-Foot-°F".
- Read the converted result, which updates instantly as you type or change units.
- Use the swap (⇅) button if you need to reverse the conversion direction.
- Use the copy button to grab the result for a materials comparison or heat transfer calculation.
Formula & Methodology
The converter's base unit is watts per metre-Kelvin (W/m·K). Every supported unit has a fixed multiplier: - 1 BTU/(hr·ft·°F) ≈ 1.73073 W/m·K - 1 cal/(s·cm·°C) = 418.4 W/m·K - 1 BTU·in/(hr·ft²·°F) ≈ 0.144228 W/m·K Any conversion follows: Result = Input × (toBase of source unit ÷ toBase of target unit) Worked example — converting copper's thermal conductivity of 400 W/m·K to BTU/(hr·ft·°F): Result = 400 × (1 ÷ 1.73073) = 231.15 BTU/(hr·ft·°F) This matches the commonly cited imperial-unit value for copper's excellent thermal conductivity.
Frequently Asked Questions