Partial Pressure Calculator
ChemistryCalculate partial pressure of gas components using Dalton's law: P_i = x_i × P_total. Supports up to 4 gas components with mole fraction calculation.
Partial Pressure Gas 1 (atm)
Breakdown
How the total splits
What is a Partial Pressure?
The Partial Pressure Calculator computes the partial pressure of each component in a gas mixture using Dalton's law: P_i = x_i × P_total, where x_i = n_i / n_total is the mole fraction of component i. Enter the total pressure (in atm) and the number of moles of up to four gas components to get the partial pressure of each gas and the mole fraction of the first component.
Dalton's law of partial pressures — that each gas in a mixture exerts pressure independently and the total pressure is the sum of partial pressures — is a foundational result of the kinetic theory of ideal gases. It is used across gas stoichiometry (equilibrium constant Kp calculations), atmospheric science (oxygen partial pressure at altitude), physiology (alveolar gas exchange), industrial gas processes, and analytical chemistry.
Partial pressure links directly to the equilibrium constant Kp (see Kp Calculator), which is expressed in terms of equilibrium partial pressures of reacting gases. It also links to Raoult's law (see Raoult's Law Calculator), which gives the partial pressure of each liquid component above an ideal solution.
How to use this Partial Pressure calculator
- Enter the Total Pressure of the gas mixture in atm.
- Enter Moles of Gas 1 and Moles of Gas 2 — the required components.
- Enter Moles of Gas 3 and Moles of Gas 4 if present, or leave at 0 for a simpler mixture.
- Read Partial Pressure Gas 1 (atm) as the highlighted primary result.
- Note the Mole Fraction Gas 1 for use in Raoult's law, Kp expressions, or Henry's law calculations.
Formula & Methodology
Dalton's law of partial pressures:P_i = x_i × P_total x_i = n_i / n_total (mole fraction) n_total = n₁ + n₂ + n₃ + n₄ Σ P_i = P_total (verification)Worked example — alveolar gas mixture at sea level: Gas mixture: N₂ (78.09%), O₂ (20.95%), CO₂ (0.04%), H₂O vapour (0.92%) by mole fraction at 760 mmHg. Use mole fractions directly as effective "moles" relative to 100:n_N₂ = 78.09, n_O₂ = 20.95, n_CO₂ = 0.04, n_H₂O = 0.92 n_total = 100 P(N₂) = 78.09/100 × 760 = 593.5 mmHg = 0.781 atm P(O₂) = 20.95/100 × 760 = 159.2 mmHg = 0.209 atm P(CO₂) = 0.04/100 × 760 = 0.30 mmHg ≈ 0.0004 atm P(H₂O) = 0.92/100 × 760 = 7.0 mmHg = 0.009 atmFor inspired air in the lungs at body temperature (37°C), water vapour saturates at 47.1 mmHg, giving actual inspired PO₂ = (760 − 47.1) × 0.2095 = 149.3 mmHg — the quantity used in the alveolar gas equation for respiratory physiology.
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