Langmuir Isotherm Calculator
ChemistryCalculate surface coverage (θ), amount adsorbed (q), and saturation capacity from Langmuir adsorption isotherm: q = qₘ × K × C / (1 + K × C).
Amount Adsorbed (q_e, mg/g)
What is a Langmuir?
The Langmuir Isotherm Calculator computes the equilibrium amount adsorbed (q_e), surface coverage (θ), separation factor (R_L), and isotherm favorability from the Langmuir equation: q_e = qₘ × K_L × C_e / (1 + K_L × C_e). Enter the maximum adsorption capacity (qₘ), Langmuir constant (K_L), and equilibrium concentration (C_e).
The Langmuir isotherm (Irving Langmuir, 1916, Nobel Prize Chemistry 1932) is the theoretical framework for monolayer adsorption on uniform surfaces. It is the most widely used model in adsorption research for water treatment, catalysis, and surface science. When the isotherm is favorable (0 < R_L < 1), the adsorbate preferentially partitions onto the surface — the basis of activated carbon filters, zeolite adsorption, and affinity chromatography.
For context on the chemical oxygen demand reduced by adsorption, the Chemical Oxygen Demand Calculator quantifies the pollutant loading. The Activity Coefficient Calculator and Ionic Strength Calculator influence adsorption in electrolyte solutions through activity effects.
How to use this Langmuir calculator
- Fit experimental (C_e, q_e) data to the linearised Langmuir equation to obtain qₘ and K_L. Or use published values from literature.
- Enter qₘ (mg/g) — the monolayer saturation capacity.
- Enter K_L (L/mg) — the Langmuir affinity constant.
- Enter C_e (mg/L) — the equilibrium concentration at the operating condition.
- Read q_e and θ for the adsorption loading, and R_L for favorability.
Formula & Methodology
Langmuir isotherm equation:q_e = qₘ × K_L × C_e / (1 + K_L × C_e) θ = q_e / qₘ = K_L × C_e / (1 + K_L × C_e) R_L = 1 / (1 + K_L × C_0) [C_0 = initial concentration] Linearised: C_e/q_e = 1/(qₘ × K_L) + C_e/qₘ Slope = 1/qₘ; Intercept = 1/(qₘ × K_L)Worked example — fluoride removal by activated alumina: qₘ = 12 mg F⁻/g; K_L = 0.08 L/mg. Initial groundwater F⁻ = 5 mg/L (WHO limit: 1.5 mg/L; Indian drinking water standard BIS IS:10500: 1.0 mg/L maximum permissible).q_e = 12 × 0.08 × 5 / (1 + 0.08 × 5) = 4.8/1.4 = 3.43 mg/g θ = 3.43/12 = 0.286 (28.6% surface covered) R_L = 1/(1 + 0.08 × 5) = 1/1.4 = 0.714 (favorable isotherm)For a 1000 L/day treatment capacity with 5 mg/L initial fluoride target to 1 mg/L effluent: fluoride to remove = (5−1) × 1000 L/day = 4000 mg/day. At q_e = 3.43 mg/g at equilibrium C_e: adsorbent needed ≈ 4000/3.43 ≈ 1165 g/day. India has 27 million people in fluorosis-endemic districts (Rajasthan, UP, Bihar, AP, Telangana) — defluoridation using the Nalgonda technique and activated alumina is a major public health intervention under JJBY/Jal Jeevan Mission.
Frequently Asked Questions