Langmuir Isotherm Calculator
ChemistryCalculate surface coverage (θ), amount adsorbed (q), and saturation capacity from Langmuir adsorption isotherm: q = qₘ × K × C / (1 + K × C).
Reviewed by the thecalcu.com team · Last updated January 11, 2025
Amount Adsorbed (q_e, mg/g)
What is a Langmuir?
The Langmuir Isotherm Calculator computes the equilibrium amount adsorbed (q_e), surface coverage (θ), separation factor (R_L), and isotherm favorability from the Langmuir equation: q_e = qₘ × K_L × C_e / (1 + K_L × C_e). Enter the maximum adsorption capacity (qₘ), Langmuir constant (K_L), and equilibrium concentration (C_e).
The Langmuir isotherm (Irving Langmuir, 1916, Nobel Prize Chemistry 1932) is the theoretical framework for monolayer adsorption on uniform surfaces. It is the most widely used model in adsorption research for water treatment, catalysis, and surface science. When the isotherm is favorable (0 < R_L < 1), the adsorbate preferentially partitions onto the surface, the basis of activated carbon filters, zeolite adsorption, and affinity chromatography.
For context on the chemical oxygen demand reduced by adsorption, the Chemical Oxygen Demand Calculator quantifies the pollutant loading. The Activity Coefficient Calculator and Ionic Strength Calculator influence adsorption in electrolyte solutions through activity effects.
Why Use a Langmuir Isotherm Calculator?
Computing q_e = qₘKC/(1+KC) with units (mg/g, L/mg, mg/L) is straightforward but the surface coverage θ = q_e/qₘ and the separation factor R_L = 1/(1+KC) require additional steps. This calculator computes all four outputs simultaneously and provides the isotherm type classification.
For fitting experimental data, the linearised Langmuir plot (C_e/q_e vs C_e) gives qₘ and K_L; enter those fitted values here to predict q_e at any equilibrium concentration on the isotherm.
Who Should Use This Calculator?
Environmental engineers and researchers studying water treatment by adsorption, dye, fluoride, arsenic, or heavy metal removal in batch and column systems.
Chemical engineering students learning mass transfer, adsorption equilibria, and unit operations, Langmuir isotherm is a standard topic in GATE chemical engineering (Paper CH).
Pharmaceutical scientists studying drug adsorption onto excipients, active packaging, and drug delivery carriers.
Soil scientists and agricultural researchers studying nutrient adsorption-desorption on Indian soils (phosphate adsorption on red laterite soils, pesticide adsorption on black cotton soils).
What Insights Does the Langmuir Isotherm Calculator Give You?
Amount Adsorbed (q_e, mg/g) is the primary output, the equilibrium loading at the given C_e. Compare to qₘ to assess how close the surface is to saturation.
Surface Coverage (θ) = q_e/qₘ, fraction of surface sites occupied (0 = empty surface; 1 = fully saturated monolayer).
Separation Factor (R_L) = 1/(1+K_L × C_e), dimensionless favorability indicator.
Isotherm Type classifies favorability: favorable (0 < R_L < 1), linear (R_L = 1), unfavorable (R_L > 1), or irreversible (R_L → 0).
How to use this Langmuir calculator
- Fit experimental (C_e, q_e) data to the linearised Langmuir equation to obtain qₘ and K_L. Or use published values from literature.
- Enter qₘ (mg/g), the monolayer saturation capacity.
- Enter K_L (L/mg), the Langmuir affinity constant.
- Enter C_e (mg/L), the equilibrium concentration at the operating condition.
- Read q_e and θ for the adsorption loading, and R_L for favorability.
Show formula & methodology ↓Show less ↑
Formula & Methodology
Langmuir isotherm equation:q_e = qₘ × K_L × C_e / (1 + K_L × C_e) θ = q_e / qₘ = K_L × C_e / (1 + K_L × C_e) R_L = 1 / (1 + K_L × C_0) [C_0 = initial concentration] Linearised: C_e/q_e = 1/(qₘ × K_L) + C_e/qₘ Slope = 1/qₘ; Intercept = 1/(qₘ × K_L)Worked example, fluoride removal by activated alumina: qₘ = 12 mg F⁻/g; K_L = 0.08 L/mg. Initial groundwater F⁻ = 5 mg/L (WHO limit: 1.5 mg/L; Indian drinking water standard BIS IS:10500: 1.0 mg/L maximum permissible).q_e = 12 × 0.08 × 5 / (1 + 0.08 × 5) = 4.8/1.4 = 3.43 mg/g θ = 3.43/12 = 0.286 (28.6% surface covered) R_L = 1/(1 + 0.08 × 5) = 1/1.4 = 0.714 (favorable isotherm)For a 1000 L/day treatment capacity with 5 mg/L initial fluoride target to 1 mg/L effluent: fluoride to remove = (5−1) × 1000 L/day = 4000 mg/day. At q_e = 3.43 mg/g at equilibrium C_e: adsorbent needed ≈ 4000/3.43 ≈ 1165 g/day. India has 27 million people in fluorosis-endemic districts (Rajasthan, UP, Bihar, AP, Telangana), defluoridation using the Nalgonda technique and activated alumina is a major public health intervention under JJBY/Jal Jeevan Mission.
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