Detention Time Calculator
ChemistryCalculate hydraulic detention time (HDT) for water treatment tanks, sedimentation basins, and clarifiers. Find tank volume, flow rate, and residence time.
Detention Time (HDT)
What is a Detention Time?
The Detention Time Calculator computes the hydraulic detention time (HDT = V/Q) for water treatment tanks, sedimentation basins, mixing chambers, and clarifiers. Enter the tank volume (m³) and flow rate (m³/hr) and select the output time unit.
Hydraulic Detention Time is the average time water spends in a treatment unit: HDT = Volume/Flow Rate. It is the primary design parameter for physical treatment processes — sedimentation requires 2–4 hours for particles to settle; flash mixing requires 30–120 seconds for coagulant dispersion; chlorine contact chambers require 30 minutes for disinfection. All Indian municipal water treatment plants designed under CPHEEO guidelines are sized based on target HDT for each unit operation.
For bioreactor applications where the biological community is affected by retention time, the Hydraulic Retention Time Calculator handles HRT with organic loading rate calculations. For effluent quality, the Chemical Oxygen Demand Calculator computes the COD of the influent wastewater being treated.
How to use this Detention Time calculator
- Enter Tank Volume (m³) — for sedimentation basins, include only the settling zone volume.
- Enter Flow Rate (m³/hr) — use design flow rate (typically peak hour flow for WTPs; average daily flow for STPs).
- Select Report Time In (minutes, hours, or days) — match the unit to your design standard.
- Read Detention Time and compare against CPHEEO standards for the unit operation.
- If HDT is too short (< 2 hr for sedimentation), increase tank volume or reduce flow rate.
Formula & Methodology
Hydraulic Detention Time:HDT = V / Q [V in m³; Q in m³/hr → HDT in hours] [V in m³; Q in m³/day → HDT in days] Unit conversions: 1 hour = 60 minutes = 1/24 day 1 MLD (megalitres/day) = 1000 m³/day = 41.67 m³/hrWorked example — Mumbai water treatment plant sedimentation basin: A WTP at Bhandup, Mumbai treats 600 MLD (megalitres per day). Sedimentation basin design: Q = 600,000 m³/day = 25,000 m³/hr. Target HDT = 3 hours (CPHEEO recommendation for turbid monsoon water).V = HDT × Q = 3 hr × 25,000 m³/hr = 75,000 m³ For 4 m depth: Basin area = 75,000 / 4 = 18,750 m² Surface Overflow Rate = Q/A = 25,000 m³/hr × 24 / 18,750 m² = 32 m/day (within CPHEEO max SOR of 33 m/day ✓)Mumbai's Bhandup Water Treatment Plant (actual capacity: ~1,900 MLD) operates multiple parallel sedimentation basins designed on this principle — serving 3+ million people in Eastern Mumbai. This is the same calculation used by MCGM's (Municipal Corporation of Greater Mumbai) engineering department for plant expansion under JNNURM Phase III.
Frequently Asked Questions