Buffer pH Calculator
ChemistryCalculate buffer solution pH using the Henderson-Hasselbalch equation. Enter pKa and acid/conjugate base concentrations to get buffer pH and buffer capacity indicator.
Buffer pH
What is a Buffer pH?
The Buffer pH Calculator computes the pH of a buffer solution using the Henderson-Hasselbalch equation: pH = pKa + log₁₀([A⁻]/[HA]). Enter the pKa of the weak acid and the molar concentrations of the acid (HA) and its conjugate base (A⁻), and the calculator returns buffer pH, the [A⁻]/[HA] ratio, and the effective buffer range (pKa ± 1).
A buffer solution resists pH change when small amounts of strong acid or base are added to it. This resistance arises from the equilibrium between a weak acid and its conjugate base. When acid is added, the conjugate base (A⁻) neutralises the H⁺; when base is added, the weak acid (HA) neutralises the OH⁻. The resulting pH shift is governed by the change in the [A⁻]/[HA] ratio, not by the absolute quantity of H⁺ added — which is why the pH barely shifts for reasonable additions of strong acid or base.
The Henderson-Hasselbalch equation quantifies this relationship. At equal concentrations of acid and conjugate base ([A⁻] = [HA]), the ratio is 1, log(1) = 0, and pH = pKa exactly. Increasing the proportion of conjugate base shifts pH above pKa; decreasing it shifts pH below pKa. The effective buffer range — where both components are present in useful amounts and the buffer can absorb either added acid or base — is pKa ± 1.
Common buffer systems in Indian chemistry and biology labs include the acetate buffer (acetic acid / sodium acetate, pKa 4.74, effective pH 3.7–5.7), the phosphate buffer (KH₂PO₄ / Na₂HPO₄, pKa 7.21, effective pH 6.2–8.2), and the carbonate buffer (H₂CO₃ / HCO₃⁻, pKa 6.35, effective pH 5.4–7.4). The physiological blood buffer at pH 7.4 uses the bicarbonate-carbonic acid system regulated by CO₂ exhalation.
For a deeper analysis of the Henderson-Hasselbalch equation — including different concentration combinations and the [H⁺] output — see the dedicated Henderson-Hasselbalch Calculator. To find the pKa of your acid from its Ka, use the pKa Calculator.
How to use this Buffer pH calculator
- Choose your weak acid and find its pKa — select an acid whose pKa is within ±1 of your target pH. Use the pKa Calculator to convert Ka to pKa if you have Ka from a reference. Common pKa values: acetic acid = 4.74, dihydrogen phosphate = 7.21, ammonium ion = 9.25.
- Enter pKa of Weak Acid — type the pKa value into the pKa of Weak Acid field. For acetic acid, enter 4.74.
- Enter Concentration of Acid (HA) — type the molar concentration of the weak acid (HA) into the Concentration of Acid (HA) field (unit: mol/L). For example, 0.1 mol/L for a 0.1 M solution.
- Enter Concentration of Conjugate Base (A⁻) — type the molar concentration of the conjugate base (typically the sodium or potassium salt) into the Concentration of Conjugate Base (A⁻) field (unit: mol/L).
- Read Buffer pH — the highlighted output shows the resulting pH. Compare this to your target. If it is too high, increase the acid concentration or decrease the base concentration to lower the [A⁻]/[HA] ratio.
- Check [A⁻]/[HA] Ratio and Effective Range — confirm the ratio is between 0.1 and 10 and that your target pH falls within the stated effective range. For finer control over the buffer composition, take these values to the Henderson-Hasselbalch Calculator.
Formula & Methodology
Henderson-Hasselbalch equation: > pH = pKa + log₁₀([A⁻]/[HA]) Where: - pKa = −log₁₀(Ka) of the weak acid - [A⁻] = molar concentration of conjugate base (mol/L) - [HA] = molar concentration of weak acid (mol/L) Rearrangements for buffer design: To find the required ratio for a target pH: > [A⁻]/[HA] = 10^(pH_target − pKa) Effective buffer range: > pH_effective = pKa ± 1 (corresponding to [A⁻]/[HA] ratios of 0.1 to 10) Worked example 1 — Acetate buffer preparation: Prepare a buffer at pH 5.0 using acetic acid (pKa = 4.74): - Required ratio: [A⁻]/[HA] = 10^(5.0 − 4.74) = 10^(0.26) = 1.82 - To prepare 0.1 M total buffer: use acid concentration = 0.1 ÷ (1 + 1.82) = 0.0355 M; conjugate base = 0.0645 M - Verification: pH = 4.74 + log(0.0645/0.0355) = 4.74 + log(1.82) = 4.74 + 0.26 = 5.00 ✓ Worked example 2 — JEE-style problem: A buffer contains 0.2 mol/L CH₃COOH and 0.3 mol/L CH₃COONa. Given Ka = 1.8 × 10⁻⁵ (pKa = 4.74): - [A⁻]/[HA] = 0.3/0.2 = 1.5 - pH = 4.74 + log(1.5) = 4.74 + 0.176 = 4.92 - Effective range: pKa ± 1 = 3.74 to 5.74 — this pH falls within range ✓ Common buffers and their pKa values: | Buffer system | Acid | pKa | Effective pH range | |---|---|---|---| | Acetate | CH₃COOH / CH₃COO⁻ | 4.74 | 3.7–5.7 | | Phosphate | H₂PO₄⁻ / HPO₄²⁻ | 7.21 | 6.2–8.2 | | HEPES | — | 7.55 | 6.8–8.2 | | Tris-HCl | Tris-H⁺ / Tris | 8.07 | 7.0–9.0 | | Borate | H₃BO₃ / B(OH)₄⁻ | 9.24 | 8.2–10.2 |
Frequently Asked Questions